PHP将二维数组某一个字段相同的数组合并起来的方法

本文实例讲述了PHP将二维数组某一个字段相同的数组合并起来的方法。分享给大家供大家参考，具体如下：

例子：

array(3) { [0]=> array(16) {  ["id"]=>  string(2) "42"  ["uid"]=>  string(2) "14"  ["euid"]=>  string(2) "56"  ["did"]=>  string(1) "1"  ["nid"]=>  string(1) "0"  ["phonetime"]=>  string(10) "1443927600"  ["createtime"]=>  string(10) "1443880619"  ["type"]=>  string(1) "3"  ["status"]=>  string(1) "0"  ["atype"]=>  string(1) "1"  ["mtype"]=>  string(1) "2"  ["endtime"]=>  string(1) "0"  ["time"]=>  string(10) "10月04日"  ["date"]=>  string(6) "周日"  ["uname"]=>  NULL  ["album"]=>  string(0) "" } [1]=> array(16) {  ["id"]=>  string(2) "40"  ["uid"]=>  string(2) "14"  ["euid"]=>  string(2) "56"  ["did"]=>  string(1) "1"  ["nid"]=>  string(1) "0"  ["phonetime"]=>  string(10) "1444359600"  ["createtime"]=>  string(10) "1444268595"  ["type"]=>  string(1) "3"  ["status"]=>  string(1) "0"  ["atype"]=>  string(1) "1"  ["mtype"]=>  string(1) "2"  ["endtime"]=>  string(1) "0"  ["time"]=>  string(10) "10月09日"  ["date"]=>  string(6) "周五"  ["uname"]=>  NULL  ["album"]=>  string(0) "" } [2]=> array(16) {  ["id"]=>  string(2) "43"  ["uid"]=>  string(1) "2"  ["euid"]=>  string(2) "56"  ["did"]=>  string(1) "1"  ["nid"]=>  string(1) "0"  ["phonetime"]=>  string(10) "1444359620"  ["createtime"]=>  string(10) "1444268595"  ["type"]=>  string(1) "3"  ["status"]=>  string(1) "0"  ["atype"]=>  string(1) "1"  ["mtype"]=>  string(1) "2"  ["endtime"]=>  string(1) "0"  ["time"]=>  string(10) "10月09日"  ["date"]=>  string(6) "周五"  ["uname"]=>  NULL  ["album"]=>  string(0) "" }}

现在想要对这个二维数组下的元素，time相同的合并到同一数组下。想要的效果为：

array(2) { ["10月04日"]=> array(1) {  [0]=>  array(16) {   ["id"]=>   string(2) "42"   ["uid"]=>   string(2) "14"   ["euid"]=>   string(2) "56"   ["did"]=>   string(1) "1"   ["nid"]=>   string(1) "0"   ["phonetime"]=>   string(10) "1443927600"   ["createtime"]=>   string(10) "1443880619"   ["type"]=>   string(1) "3"   ["status"]=>   string(1) "0"   ["atype"]=>   string(1) "1"   ["mtype"]=>   string(1) "2"   ["endtime"]=>   string(1) "0"   ["time"]=>   string(10) "10月04日"   ["date"]=>   string(6) "周日"   ["uname"]=>   NULL   ["album"]=>   string(0) ""  } } ["10月09日"]=> array(2) {  [0]=>  array(16) {   ["id"]=>   string(2) "40"   ["uid"]=>   string(2) "14"   ["euid"]=>   string(2) "56"   ["did"]=>   string(1) "1"   ["nid"]=>   string(1) "0"   ["phonetime"]=>   string(10) "1444359600"   ["createtime"]=>   string(10) "1444268595"   ["type"]=>   string(1) "3"   ["status"]=>   string(1) "0"   ["atype"]=>   string(1) "1"   ["mtype"]=>   string(1) "2"   ["endtime"]=>   string(1) "0"   ["time"]=>   string(10) "10月09日"   ["date"]=>   string(6) "周五"   ["uname"]=>   NULL   ["album"]=>   string(0) ""  }  [1]=>  array(16) {   ["id"]=>   string(2) "43"   ["uid"]=>   string(1) "2"   ["euid"]=>   string(2) "56"   ["did"]=>   string(1) "1"   ["nid"]=>   string(1) "0"   ["phonetime"]=>   string(10) "1444359620"   ["createtime"]=>   string(10) "1444268595"   ["type"]=>   string(1) "3"   ["status"]=>   string(1) "0"   ["atype"]=>   string(1) "1"   ["mtype"]=>   string(1) "2"   ["endtime"]=>   string(1) "0"   ["time"]=>   string(10) "10月09日"   ["date"]=>   string(6) "周五"   ["uname"]=>   NULL   ["album"]=>   string(0) ""  } }}

那么。。。代码很简单，没有想象的那么复杂，想要的结果是个三维数组

$result 为原二维数组

$res = array(); //想要的结果foreach ($result as $k => $v) {  $res[$v["time"]][] = $v;}

更多关于PHP相关内容感兴趣的读者可查看本站专题：《php面向对象程序设计入门教程》、《php字符串(string)用法总结》、《php+mysql数据库操作入门教程》及《php常见数据库操作技巧汇总》

希望本文所述对大家PHP程序设计有所帮助。